2x^2+3((-2x+13)/3)^2-35=0

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Solution for 2x^2+3((-2x+13)/3)^2-35=0 equation:


x in (-oo:+oo)

3*((13-2*x)/3)^2+2*x^2-35 = 0

(3*(13-2*x)^2)/(3^2)+2*x^2-35 = 0

(3*(13-2*x)^2)/(3^2)+(2*3^2*x^2)/(3^2)+(-35*3^2)/(3^2) = 0

3*(13-2*x)^2+2*3^2*x^2-35*3^2 = 0

30*x^2-156*x-315+507 = 0

30*x^2-156*x+192 = 0

30*x^2-156*x+192 = 0

6*(5*x^2-26*x+32) = 0

5*x^2-26*x+32 = 0

DELTA = (-26)^2-(4*5*32)

DELTA = 36

DELTA > 0

x = (36^(1/2)+26)/(2*5) or x = (26-36^(1/2))/(2*5)

x = 16/5 or x = 2

6*(x-2)*(x-16/5) = 0

(6*(x-2)*(x-16/5))/(3^2) = 0

(6*(x-2)*(x-16/5))/(3^2) = 0 // * 9

6*(x-2)*(x-16/5) = 0

( x-16/5 )

x-16/5 = 0 // + 16/5

x = 16/5

( x-2 )

x-2 = 0 // + 2

x = 2

x in { 16/5, 2 }

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